andy chung . iamchung . revisit to project euler with c++

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revisit to project euler with c++

revisit to project euler with c++

As a way to get reacquainted with c++, I’m revisiting all my PE problems. Here’s the code for #1.

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

#include <iostream>

int main(int argc, char* argv[])
{
    int iMax = 1000;
    int iSum = 0;
    int iMultiplesOf[2] = { 3, 5 };
    for each (int iNum in iMultiplesOf)
    {
        for (int i = 0; i * iNum < iMax; i++)
        {
            iSum += i * iNum;
        }
    }
    std::cout << iSum << std::endl;
    system("PAUSE");
    return 0;
}