# revisit to project euler with c++

As a way to get reacquainted with c++, I'm revisiting all my PE problems. Here's the code for #1.

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

```
#include <iostream>
int main(int argc, char* argv[])
{
int iMax = 1000;
int iSum = 0;
int iMultiplesOf[2] = { 3, 5 };
for each (int iNum in iMultiplesOf)
{
for (int i = 0; i * iNum < iMax; i++)
{
iSum += i * iNum;
}
}
std::cout << iSum << std::endl;
system("PAUSE");
return 0;
}
```